If the sum of three consecutive terms of an increasing A.P. is 51 and the product of the first and third of these terms is 273, then the third term is

Question

KollegeApply · Accepted Answer

In the given problem, the sum of three consecutive terms of an A.P is 51 and the product of the first and the third terms is 273. We need to find the third term. Here, Let the three terms be (a-d),a,(a + d) where, a is the first term and d is the common difference of the A.P So, (a - d) + a + ( a + d) = 51 3a = 51 a = $\frac{51}{3}$ a = 17 Also, ( a - d) ( a + d ) = 273 a2 - d2 = 273 [ Using a2 - d2 = (a + b ) (a - b)] 172 - d2 = 273 289 - d2 = 273 Further solving for d, Now, it is given that this is an increasing A.P. so d cannot be negative. So, d = 4 Substituting the values of a and d in the expression for the third term, we get, Third term = a + d So, a + d = 17 + 4 = 21 Therefore, the third term is a3 = 21

AChoose Your Answer