If x tan $45^\circ$ cos $60^\circ$ = sin $60^\circ$ cot $60^\circ$, then x is equal to

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Given that: `x tan $45^\circ$ cos $60^\circ$=sin $60^\circ$ cot $60^\circ$` Here we have to find the value of x We know that ` tan $45^\circ$=1, cos $60^\circ$=$\frac{1}{2}$ , sin $60^\circ$=sqrt3/2,cot $60^\circ$=1/sqrt3 $\Rightarrow$ x tan $45^\circ$ cos $60^\circ$= sin $60^\circ$ cot $60^\circ$ $\Rightarrow$ x xx1xx1/2=sqrt3/2xx1/sqrt3 $\Rightarrow$ x=1`

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