If y = log ((1 - x^2)/(1 + x^2)), then "dy"/"dx" is equal to ______.

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If y = log ((1 - x^2)/(1 + x^2)), then "dy"/"dx" is equal to (-4x)/(1 - x^4). Explanation: Given that: y = log ((1 - x^2)/(1 + x^2)) $\Rightarrow$ y = log(1 – x2) – log(1 + x2) ....`[because log x/y = log x - log y]` Differentiating both sides w.r.t. x `"dy"/"dx" = 1/(1 - x^2) * "d"/"dx"(1 - x^2) - 1/(1 + x^2) (1 + x^2) = (-2x)/(1 - x^2) - (2x)/(1 + x^2) = (-2x - 2x^3 - 2x + 2x^3)/((1 - x^2)(1 + x^2)) = (-4x)/(1 - x^4)`.

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