If y = (sin−1 x)2, then (1 − x2)y2 is equal to

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(a) xy1 + 2 Here, y = \left( \sin^{- 1} x \right)^2 \text { Now,} y_1 = 2 \sin^{- 1} x 1/$\sqrt$(1 - x^2) \Rightarrow y_2 = $\frac{2}{1}$ - x^2 + \frac{2x \sin^{- 1} x}{\left( 1 - x^2 \right)^{$\frac{3}{2}$}} \Rightarrow y_2 = $\frac{2}{1}$ - x^2 + \frac{2x \sin^{- 1} x}{\left( 1 - x^2 \right)$\sqrt$(1 - x^2)} \Rightarrow y_2 = $\frac{2}{1}$ - x^2 + \frac{x y_1}{\left( 1 - x^2 \right)} \Rightarrow y_2 \left( 1 - x^2 \right) = 2 + x y_1

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