In a simple harmonic motion

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KollegeApply · Accepted Answer

the average potential energy in one time period is equal to the average kinetic energy in this period. The kinetic energy of the motion is given as, $\frac{1}{2}$k A^2 \cos^2 \omega t The potential energy is calculated as, $\frac{1}{2}$k A^2 \sin^2 \omega t As the average of the cosine and the sine function is equal to each other over the total time period of the functions, the average potential energy in one time period is equal to the average kinetic energy in this period.

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