In an extrinsic semiconductor, the number density of holes is 4 $\times$ 1020 m-3. If the number density of intrinsic carriers is 1.2 $\times$ 1015 m-3, the number density of electrons in it is ______.

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In an extrinsic semiconductor, the number density of holes is 4 $\times$ 1020 m-3. If the number density of intrinsic carriers is 1.2 $\times$ 1015 m-3, the number density of electrons in it is 3.6 $\times$ 109 m-3. Explanation: We know that, Number of density of electrons = (n_i^2)/(n_h) Where, ni is density of intrinsic carrier, nh is the density of holes. Given: n_i = 1.2 xx 10^15 m-3 n_h = 4 xx 10^20 m-3 n_e = (n_i^2)/(n_h) `n_e = (1.2 xx 10^15)^2/(4 xx 10^20) n_e = 3.6 xx 10^9` m-3

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