In an isothermal process on an ideal gas, the pressure increases by 0.5%. The volume decreases by about

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KollegeApply · Accepted Answer

0.5% Let p and p' be the initial and final pressures of the system and V and V' be the initial and final volumes of the system. p' is 0.5% more than p and the process is isothernal. So, pV = k = p'V' = constant. Therefore, pV = p'V' `=> "p"^"V" = ("P" +0.$\frac{5}{100}$"p")"V" => "p"^"V" = 100.$\frac{5}{100}$"p"^("V'") => "V'" = $\frac{100}{100}$.5"V" => "V'" -"V" = $\frac{100}{100}$.5 "V"-"V" = -0.$\frac{5}{100}$.5` = -0.49 % So, volume V' decreases by about 0.5% of V.

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