It is given that ΔABC ~ ΔPQR, with (BC)/(QR) = $\frac{1}{3}$. Then, (ar(PRQ))/(ar(BCA)) is equal to ______.

Question

KollegeApply · Accepted Answer

It is given that ΔABC ~ ΔPQR, with (BC)/(QR) = $\frac{1}{3}$. Then, (ar(PRQ))/(ar(BCA)) is equal to 9. Explanation: Given, ∆ABC ~ ∆PQR and ("BC")/("QR") = $\frac{1}{3}$ We know that, the ratio of the areas of two similar triangles is equal to square of the ratio of their corresponding sides. $\therefore$ `("ar(∆PRQ)")/("ar(∆BCA)") = ("QR")^2/("BC")^2 = (("QR")/("BC"))^2 = ($\frac{3}{1}$)^2 = $\frac{9}{1}$` = 9

AChoose Your Answer