Let $\theta$ denote the angular displacement of a simple pendulum oscillating in a vertical plane. If the mass of the bob is m, the tension is the string is mg cos $\theta$

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at the extreme positions Tension is the string , 	ext{T} = \frac{	ext{mv}^2}{	ext{r}} - 	ext{mg}\cosθ When v = 0, \left| 	ext{T} ight| = 	ext{mg}\cosθ That is, at the extreme positions, the tension is the string is mgcosθ.

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