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Let I1 = int_"e"^("e"^2) 1/logx "d"x and I2 = int_1^2 ("e"^x)/x "d"x then
Mathematics and Statistics (Arts and Science)
Definite Integration
Question
Updated
19 Aug 2026
Let I1 = int_"e"^("e"^2) 1/logx "d"x and I2 = int_1^2 ("e"^x)/x "d"x then
A
Choose Your Answer
A
I 1 = \(\frac{1}{3}\) "I"_2
B
I 1 + I 2 = 0
C
I 1 = 2I 2
D
I 1 = I 2
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