Mark the correct alternative in the following question: For the following probability distribution: X : 1 2 3 4 P(X) : $\frac{1}{10}$ $\frac{1}{5}$ $\frac{3}{10}$ $\frac{2}{5}$ The value of E(X2) is

Question

KollegeApply · Accepted Answer

The probability distribution of X is given below: X : 1 2 3 4 P(X) : $\frac{1}{10}$ $\frac{1}{5}$ $\frac{3}{10}$ $\frac{2}{5}$ E\left( X^2 \right) = 1^2 $\times$ $\frac{1}{10}$ + 2^2 $\times$ $\frac{1}{5}$ + 3^2 $\times$ $\frac{3}{10}$ + 4^2 $\times$ $\frac{2}{5}$ = $\frac{1}{10}$ + $\frac{8}{10}$ + $\frac{27}{10}$ + $\frac{64}{10}$ = $\frac{100}{10}$ = 10

AChoose Your Answer