Pb has fcc structure with edge length of unit cell 495 pm. Radius of Pb atom is ______.

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KollegeApply · Accepted Answer

Pb has fcc structure with edge length of unit cell 495 pm. Radius of Pb atom is 175 pm. Explanation: Given: a = 495 pm Radius, r = ? For fee structure radius = r = `a/(2sqrt2) = 495/(2sqrt2) = 175` cm The radius of the Cu atom = is 175 pm.

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