ΔPQR ~ ΔABC, (PR)/(AC) = $\frac{5}{7}$, then

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KollegeApply · Accepted Answer

ΔABC is greater. Explanation: Similar triangles have corresponding sides in the same ratio, so the scale factor from ΔABC to ΔPQR is: (PR)/(AC) = $\frac{5}{7}$ (< 1) Meaning each side of ΔPQR is $\frac{5}{7}$ of the corresponding side of ΔABC. Areas scale as the square of the side ratio, so: `(Area(PQR))/(Area(ABC)) = ($\frac{5}{7}$)^2 = $\frac{25}{49}$ < 1` Therefore, ΔABC is greater.

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