sqrt(sec^2 $\theta$ + cocec^2 $\theta$) is equal to ______.

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KollegeApply · Accepted Answer

sqrt(sec^2 $\theta$ + cocec^2 $\theta$) is equal to sec $\theta$ cosec $\theta$. Explanation: sec $\theta$ = 1/cos $\theta$ and cosec $\theta$ = 1/sin $\theta$ `sqrt(sec^2 $\theta$ + cocec^2 $\theta$) = sqrt(1/cos^2 $\theta$ + 1/sin^2 $\theta$) = sqrt((sec^2 $\theta$ + cos^2 $\theta$)/(cos^2 $\theta$ .sin^2 $\theta$)) = sqrt(1/(cos^2 $\theta$ .sin^2 $\theta$)) = 1/(cos $\theta$.sin $\theta$) = (1/cos $\theta$)(1/sin $\theta$)` = sec$\theta$ cosec $\theta$

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