The 4th term from the end of the AP: –11, –8, –5, ..., 49 is ______.

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The 4th term from the end of the AP: –11, –8, –5, ..., 49 is 40. Explanation: We know that, the nth term of an AP from the end is an = l – (n – 1)d ...(i) Here, l = Last term and l = 49 ...[Given] Common difference, d = – 8 – (– 11) = – 8 + 11 = 3 From equation (i), a4 = 49 – (4 – 1)3 = 49 – 9 = 40

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