The 5th term from the end of G.P. 2, 4, 8, ..... 4096 is ______.

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The 5th term from the end of G.P. 2, 4, 8, ..... 4096 is 256. Explanation: Last term (l) = 4096 r = $\frac{4}{2}$ = 2 n = 5 a_n = l/(r^((n - 1))) a_5 = 4096/(2^((5 - 1))) a_5 = $\frac{4096}{2}$^4 a_5 = $\frac{4096}{16}$ a5 = 256

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