The angle of elevation of the top of a tower from a point on the ground 60 m away from the foot of tower is $30^\circ$. The height of tower is ______.

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KollegeApply · Accepted Answer

The angle of elevation of the top of a tower from a point on the ground 60 m away from the foot of tower is $30^\circ$. The height of tower is underlinebb(20sqrt(3) m). Explanation: Let h = height. tan 30^circ = h/60. Since tan 30^circ = 1/sqrt(3), h = 60 xx 1/sqrt(3) = 60/sqrt(3) = (60sqrt(3))/3 = 20sqrt(3) m

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