The area of a triangle with vertices A(3, 0), B(7, 0) and C(8, 4) is ______.

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The area of a triangle with vertices A(3, 0), B(7, 0) and C(8, 4) is 8. Explanation: Vertices of the triangle are, A(x1, y1) = (3, 0) B(x2, y2) = (7, 0) C(x3, y3) = (8, 4) Area of triangle = `|$\frac{1}{2}$[x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)]| = |$\frac{1}{2}$[3(0 - 4) + 7(4 - 0) + 8(0 - 0)]| = |$\frac{1}{2}$[-12 + 28 + 0]| = |$\frac{1}{2}$[16]|` = 8 Therefore, the area of ΔABC is 8.

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