The area of ΔABC with vertices A(3, 0), B(7, 0) and C(8, 4) is ______.

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KollegeApply · Accepted Answer

The area of ΔABC with vertices A(3, 0), B(7, 0) and C(8, 4) is 8 sq units. Explanation: AB lies on the x-axis from x = 3 to x = 7, so base AB = 4. The y-coordinate of C is 4, so the height from C to AB is 4. Area = $\frac{1}{2}$ $\times$ base $\times$ height = $\frac{1}{2}$ xx 4 xx 4 = 8 sq units

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