The area of the circle that can be inscribed in a square of side 10 cm is

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KollegeApply · Accepted Answer

We know that ABCD is a square of length 10 cm. A circle is inscribed in the square therefore, all the sides of the square are become tangents of the circle. By, the tangent property, we have AP=PD=5 AQ=QB=5 BR=RC=5 CS+DS=5 If we join PR then it will be the diameter of the circle of 10 cm. Therefore, radius of the circle = 5cm $\therefore$ Area of the circle=pir^2 $\therefore$ Area of the circle=pixx5^2 $\therefore$ Area of the circle=25pi Therefore, area of the circle is 25picm^2 [Solution diagram: 64002_solution_1.png]

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