The areas of two similar triangles are 121 cm2 and 100 cm2. If the altitude of a larger triangle is 6.6 cm, then the corresponding altitude of the smaller triangle is ______.

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The areas of two similar triangles are 121 cm2 and 100 cm2. If the altitude of a larger triangle is 6.6 cm, then the corresponding altitude of the smaller triangle is 6 cm. Explanation: For similar triangles, the ratio of areas is equal to the square of the ratio of corresponding sides (or altitudes): `"Area"_1/"Area"_2 = (h_1/h_2)^2` Let the larger triangle area = 121, the smaller = 100, and the altitude of the larger = 6.6 cm. $\frac{121}{100}$ = (6.6/h)^2 6.6/h = sqrt($\frac{121}{100}$) 6.6/h = $\frac{11}{10}$ h = 6.6 xx $\frac{10}{11}$ $\therefore$ h = 6 cm

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