The circular ends of a bucket are of radii 35 cm and 14 cm and the height of the bucket is 40 cm. Its volume is

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80080 cm3 Let R and r be the radii of the top and base of the bucket, respectively, and let h be its height. Then, R = 35 cm, r = 14 cm , h = 40 cm R = 35 cm, r = 14 cm, h = 40 cm Volume of the bucket = Volume of the frustum of the cone `=$\frac{1}{3}$pi"h"["R"^2 +"r"^2+"Rr" ] "cm"^3 = $\frac{1}{3}$ xx22/7xx40xx[(35)^2 + (14)^2 + (35xx14)] "cm"^3 =((880)/(21)xx1911) "cm"^3` = 80080 cm3 Hence, the volume of the bucket is 80080 cm3.

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