The current in a coil changes from 50A to 10A in 0.1 second. The self inductance of the coil is 20H. The induced e.m.f. in the coil is ______.

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The current in a coil changes from 50A to 10A in 0.1 second. The self-inductance of the coil is 20H. The induced e.m.f. in the coil is 8000V. Explanation: The induced e.m.f. in the coil is given by the formula: e.m.f. = -L(DeltaI)/(Deltat) Where, L= 20H (self-inductance) ΔI = final​ − Iinitial ​= 10A − 50A = −40A, Δt = 0.1 s. Substituting the values: e.m.f. = `-20 xx (-40)/0.1 = 20 xx 400 8000 V` The magnitude of the induced emf is 8000 V.

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