The diameters of the top and the bottom portions of a bucket are 42 cm and 28 cm respectively. If the height of the bucket is 24 cm, then the cost of painting its outer surface at the rate of 50 paise / cm2 is

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Radius of top of bucket r_1 = $\frac{42}{2}$ = 21 "cm" Radius of bottom of bucket r_2 = $\frac{28}{2}$ = 14 "cm" Height of bucket, h = 24 cm. l = sqrt(h^2 (r_1 - r_2)) =sqrt(576 + (21 - 14)^2) = sqrt (576 + 49) =sqrt 625 = 25 C.S.A. of the bucket = pi (r_1 + r_2)l =pi (21 +14) xx 25 =$\frac{22}{7}$ xx 35 xx 25 = 2750 cm2 Area of bottom =pir^2 = $\frac{22}{7}$ xx 196 = 616 \ cm^2 The cost of painting its C.S. , =(2750 + 616) xx $\frac{1}{2}$ =3366 xx $\frac{1}{2}$ ="Rs" 1683

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