The energy of an atom (or ion) in its ground state is −54.4 eV. It may be

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He+ The total energy of a hydrogen-like ion, having Z protons in its nucleus, is given by E = - (13.6Z^2)/(n^2)eV Here, n = Principal quantum number For ground state, n = 1 $\therefore$ Total energy, E = - 13.6 Z^2 eV For hydrogen, Z = 1 $\therefore$ Total energy, E = - 13.6 eV For deuterium, Z = 1 $\therefore$ Total energy, E = - 13.6 eV For He+, Z = 2 $\therefore$ Total energy, E = - 13.6$\times$22 = - 54.4 eV For Li++, Z = 3 $\therefore$ Total energy, E = - 13.6$\times$32 = - 122.4 eV Hence, the ion having an energy of −54.4 eV in its ground state may be He+.

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