The equation of a line passing through (2, 1) and perpendicular to the line 3x − 4y = 8 is ______.

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The equation of a line passing through (2, 1) and perpendicular to the line 3x − 4y = 8 is 4x + 3y = 11. Explanation: To get a line perpendicular to 3x − 4y = 8, Now, swap the x and y coefficients, and also change the sign between them. The form becomes: 4x + 3y = k Let’s solve for k: Substitute the point (2, 1) into the new equation: 4(2) + 3(1) = k 8 + 3 = k ∴ k = 11 Putting it all together, we get 4x + 3y = 11.

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