The function f(x) = "e"^|x| is ______.

Question

KollegeApply · Accepted Answer

The function f(x) = "e"^|x| is continuous everywhere but not differentiable at x = 0. Explanation: Given that: f(x) = "e"^|x| We know that modulus function is continuous but not differentiable in its domain. Let g(x) = |x| and t(x) = ex ∴ f(x) = got(x) = g[t(x)] = "e"^|x| Since g(x) and t(x) both are continuous at x = 0 but f(x) is not differentiable at x = 0.

AChoose Your Answer