The graph of ln ("R"/"R"_0) versus ln A (R = radius of a nucleus and A = its mass number) is ______.

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KollegeApply · Accepted Answer

The graph of ln ("R"/"R"_0) versus ln A (R = radius of a nucleus and A = its mass number) is a straight line. Explanation: The average nuclear radius (R) and the mass number of the element (A) has the following relation : "R" = "R"_0"A"^($\frac{1}{3}$) "R"/"R"_0 = "A"^($\frac{1}{3}$) In ("R"/"R"_0) = $\frac{1}{3}$ "In A" Therefore, the graph of ln ("R"/"R"_0) versus ln A is a straight line passing through the origin with slope $\frac{1}{3}$.

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