The height of a conical tent is 14 m and its floor area is 346.5 m2. How much canvas, 1.1 wide, will be required for it?

Question

KollegeApply · Accepted Answer

525 m Area of the floor of a conical tent= $\pi$r2 Therefore, $\pi$r2 = 346.5 => $\frac{22}{7}$xx"r"^2 = 346.5 => "r"^2 =((3465)/10xx7/22) => "r"^2 = $\frac{441}{4}$ => "r"^2 = ($\frac{21}{2}$)^2 => "r" = $\frac{21}{2}$ "m" Height of the cone = 14 m Slant height of the cone,"l"=sqrt("r"^2 + "h"^2) =sqrt(($\frac{21}{2}$)^2) + (14)^2 =sqrt($\frac{441}{4}$) + 196 =sqrt(1224)/4 =$\frac{35}{4}$ "m" Area of the canvas = curved surface area of the conical tent = $\pi$rl =($\frac{22}{7}$xx21/2xx35/2) = 577.5 m2 `"Length of the canvas" ="Area of the canvas"/"width of the canvas" = 577.$\frac{5}{1}$.1 "m"` = 525 m

AChoose Your Answer