The height of the vertical pole is $\sqrt$(3) times the length of its shadow on the ground, then angle of elevation of the sun at that time is

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Let the angle of elevation of the sun be $\theta$. Suppose AB is the height of the pole and BC is the length of its shadow. It is given that, AB = $\sqrt$(3)BC In right ∆ABC, \tan$\theta$ = AB/BC \Rightarrow \tan$\theta$ = $\sqrt$(3)BC/BC = $\sqrt$(3) \Rightarrow \tan$\theta$ = \tan$60^\circ$ \Rightarrow $\theta$ = $60^\circ$ Thus, the angle of elevation of the sun is 60º. [Solution diagram: 63599_solution_1.png]

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