The interval of increase of the function f(x) = x − ex + tan (2$\pi$/7) is

Question

KollegeApply · Accepted Answer

(−$\infty$, 0) f\left( x \right) = x - e^x + \tan\left( 2$\pi$/7 \right) f'\left( x \right) = 1 - e^x \text { For f(x) to be increasing, we must have } f'\left( x \right) > 0 \Rightarrow 1 - e^x > 0 \Rightarrow e^x < 1 \Rightarrow x < 0 \Rightarrow x \in \left( - \infty , 0 \right) \text { So,f(x) is increasing on } \left( - \infty , 0 \right) .

AChoose Your Answer