The length of a line segment joining A (2, −3) and B is 10 units. If the abscissa of B is 10 units, then its ordinates can be

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It is given that distance between P (2,−3) and Q ( 10 , y ) is 10. In general, the distance between A`(x_1 ,y_1) " and " B (x_2 , y_2) is given by, AB^2 = (x_2 - x_1)^2 + (y_2 - y_1)^2 So, 10^2 = (10 - 2)^2 +(y + 3)^2` On further simplification, (y + 3)^2 = 36 y = -3+- 6 = -9 , 3 We will neglect the negative value. So, y = -9 , 3

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