The length of the minute hand of a clock is 21 cm. The area swept by the minute hand in 10 minutes is

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KollegeApply · Accepted Answer

Angle subtends by the minute hand in 1 minute = 6∘ $\therefore$ Angle subtends by the minute hand in 10 minutes = 60∘ Now, Area of the sector`=theta/($360^\circ$) pi"r"^2 = $60^\circ$/$360^\circ$ xx $\frac{22}{7}$(21)^2 = 231 "cm"^2 Now, Area of the sector=theta/$360^\circ$pi"r"^2 = ($60^\circ$)/360^circxx22/7(21)^2=231 "cm"^2` Hence, the correct answer is option (a).

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