The minimum orbital angular momentum of the electron in a hydrogen atom is

Question

KollegeApply · Accepted Answer

h/2$\pi$ According to Bohr's atomic theory, the orbital angular momentum of an electron is an integral multiplt of h/2$\pi$. $\therefore$ L_u = (nh)/(2pi) Here, n = Principal quantum number The minimum value of n is 1. Thus, the minimum value of the orbital angular momentum of the electron in a hydrogen atom is given by L = h/(2pi)

AChoose Your Answer