The number of terms in the AP 5, 9, 13, 17, ..., 185 is ______.

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The number of terms in the AP 5, 9, 13, 17, ..., 185 is 46. Explanation: a = 5, common difference d = 4. nth term = a + (n – 1)d = 5 + 4(n – 1) Set equal to 185: 5 + 4(n – 1) = 185 ⇒ 4(n – 1) = 180 ⇒ n – 1 = 45 ⇒ n = 46

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