The quantity added to each term of the ratio 6 : 11 so that it becomes equal to 3 : 4 is ______.

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The quantity added to each term of the ratio 6 : 11 so that it becomes equal to 3 : 4 is 9. Explanation: Let x be the quantity added to both terms of the ratio 6 : 11 (6 + x)/(11 + x) = $\frac{3}{4}$ 4(6 + x) = 3(11 + x) 24 + 4x = 33 + 3x 4x − 3x = 33 − 24 x = 9

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