The radii of the base of a cylinder and a cone are in the ratio 3 : 4. If their heights are in the ratio 2 : 3, the ratio between their volumes is

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9 : 8 Let the radii of the base of the cylinder and cone be 3r and 4r and their heights be 2h and 3h, respectively. Then, ratio of their volumes`= (pi(3"r")^2xx(2"h"))/($\frac{1}{3}$ pi(4"r")xx(3"h")) =(9"r"^2xx2xx3)/(16"r"^2xx3 =$\frac{9}{8}$` = 9 : 8

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