The radii of the top and bottom of a bucket of slant height 45 cm are 28 cm and 7 cm, respectively. The curved surface area of the bucket is ______.

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The radii of the top and bottom of a bucket of slant height 45 cm are 28 cm and 7 cm, respectively. The curved surface area of the bucket is 4950 cm2. Explanation: Given, the radius of the top of the bucket, R = 28 cm And the radius of the bottom of the bucket, r = 7 cm Slant height of the bucket, l = 45 cm Since, bucket is in the form of frustum of a cone. $\therefore$ Curved surface area of the bucket = $\pi$l (R + r) = $\pi$ $\times$ 45(28 + 7) ...[∵ Curved surface area of frustum of a cone = $\pi$(R + r)l] = $\pi$ $\times$ 45 $\times$ 35 = $\frac{22}{7}$ xx 45 xx 35 = 4950 cm2

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