The radius of the innermost electron orbit of a hydrogen atom is 5.3 $\times$ 10–11m. The radius of the n = 3 orbit is ______.

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The radius of the innermost electron orbit of a hydrogen atom is 5.3 $\times$ 10–11m. The radius of the n = 3 orbit is `underline(bb(4.77 xx 10^-10 m))`. Explanation: The radius of an atom whose principal quantum number is n is given by r = n2r0 Where r0 = radius of innermost electron orbit for hydrogen atom and r0 = 5.3 $\times$ 10–11m For the second excited state, n = 3 $\therefore$ r = 32 $\times$ r0 = 9 $\times$ 5.3 $\times$ 10–11 r = 4.77 $\times$ 10–10m.

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