The rms speed of oxygen molecules in a gas is v. If the temperature is doubled and the oxygen molecules dissociate into oxygen atoms, the rms speed will become

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2v \text { Given }: v = $\sqrt$(3RT/32) \text { Let the new rms speed be v' } . \text { Molecule dissociate }, M = 16 v' = \sqrt{\frac{3R\left( 2T \right)}{16}} = \sqrt{\frac{3R\left( 4T \right)}{32}} = 2$\sqrt$(3RT/32) = 2v

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