The straight line x - $\frac{3}{3}$ = y - $\frac{2}{1}$ = z - $\frac{1}{0}$ is

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perpendicular to z-axis We have , x - $\frac{3}{3}$ = y - $\frac{2}{1}$ = z - $\frac{1}{0}$ Also, the given line is parallel to the vector \vec{b} = 3 \hat{i} + \hat{j} + 0 \hat{k} Let x \hat{i} + y \hat{j} + z \hat{k} be perpendicular to the given line. Now, 3x + 4y + 0z = 0 It is satisfied by the coordinates of z-axis, i.e. (0, 0, 1). Hence, the given line is perpendicular to z-axis.

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