The sum of length, breadth and height of a cuboid is 19 cm and its diagonal is 5sqrt(5) cm. Its surface area is

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KollegeApply · Accepted Answer

236 cm2 Let l, b and h be the length, breadth and height of the cuboid. Then, l + b + h = 19 ⇒ ( l + b + h )2 + 2 (lb + bh + lh) = 36 `⇒ (5sqrt(5) + 2("lb" + "bh" + "lh") = 361` ⇒ 2 (lb + bh + lh) = (361 - 125) `⇒ 2("lb" + "bh" +"lh") = 236 "cm"^2` Hence, the surface area of the cuboid is 236 cm2

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