The work function of a metal is 4.2 eV. Its threshold wavelength will be ______.

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The work function of a metal is 4.2 Ev. Its threshold wavelength will be 2959 Å. Explanation: `lambda = (hc)/phi_0 = (6.63 xx 10^-34 xx 3 xx 10^8)/(4.2 xx 1.6 xx 10^-19` = 2959.8 $\times$ 10−10 ≈ 2959 Å

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