The zeros of the polynomial 7x^2 - (11x)/3 - $\frac{2}{3}$ are ______.

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The zeros of the polynomial 7x^2 - (11x)/3 - $\frac{2}{3}$ are underlinebb($\frac{2}{3}$, (-1)/7). Explanation: `7x^2 - (11x)/3 - $\frac{2}{3}$ = (21x^2 - 11x - 2)/3`. Now, 21x2 – 11x – 2 = 21x2 – 14x + 3x – 2 = 7x(3x – 2) + (3x – 2) = (3x – 2)(7x + 1) $\therefore$ The zeros are $\frac{2}{3}$ and (-1)/7.

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