The zeros of the polynomial x^2 + $\frac{1}{6}$x - 2 are ______.

Question

KollegeApply · Accepted Answer

The zeros of the polynomial x^2 + $\frac{1}{6}$x - 2 are underlinebb((-3)/2, $\frac{4}{3}$). Explanation: `x^2 + $\frac{1}{6}$x - 2 = (6x^2 + x - 12)/6`. 6x2 + x – 12 = 6x2 + 9x – 8x – 12 = 3x(2x + 3) – 4(2x + 3) = (2x + 3)(3x – 4) $\therefore$ The zeros are (-3)/2 and $\frac{4}{3}$.

AChoose Your Answer