Three capacitors of capacitances 6 µF each are available. The minimum and maximum capacitances, which may be obtained are

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KollegeApply · Accepted Answer

2 µF, 18 µF The minimum capacitance can be obtained by connecting all capacitors in series. It can be calculated as follows : 1/C = $\frac{1}{6}$+$\frac{1}{6}$+$\frac{1}{6}$ = $\frac{1}{2}$ $\Rightarrow$ C =2 µF The maximum capacitance can be obtained by connecting all capacitors in parallel. It can be calculated as follows : C = 6+6+6 = 18 µF

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