Three identical cars A, B and C are moving at the same speed on three bridges. The car A goes on a place bridge, B on a bridge convex upward and C goes on a bridge concave upward. Let FA, FB and FC be the normal forces exerted by the car on the bridges when they are at the middle of bridges.

Question

KollegeApply · Accepted Answer

FC is maximum of the three forces. At the middle of bridge, normal force can be given as : 	ext{N}_	ext{A} = 	ext{mg} 	ext{N}_	ext{B} = \frac{	ext{mv}^2}{	ext{r}} - 	ext{mg} 	ext{N}_	ext{C} = \frac{	ext{mv}^2}{	ext{r}} + 	ext{mg} So, FC is maximum. [Solution diagram: 66617_solution_1.png]

AChoose Your Answer