To divide a line segment AB in the ratio 5 : 7, first a ray AX is drawn so that $\angle$BAX is an acute angle and then at equal distances points are marked on the ray AX such that the minimum number of these points is ______.

Question

KollegeApply · Accepted Answer

To divide a line segment AB in the ratio 5 : 7, first a ray AX is drawn so that $\angle$BAX is an acute angle and then at equal distances points are marked on the ray AX such that the minimum number of these points is 12. Explanation:- We know that to divide a line segment in the ratio m : n, first draw a ray AX which makes an acute angle BAX, then marked m + n points at equal distances from each other. Here m = 5, n = 7 So minimum number of these point = m + n = 5 + 7 = 12

AChoose Your Answer