Two bodies A and B having equal surface areas are maintained at temperature $10^\circ$C and $20^\circ$C. The thermal radiation emitted in a given time by A and B are in the ratio

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1 : 1.15 From Stefan-Boltzmann law, energy of the thermal radiation emitted per unit time by a blackbody of surface area A is given by u = σAT^4 Here, σ is Stefan-Boltzmann constant. (uA)/(uB) = "T"_"A"^4/(T_B^4) `(u_A)/ (u_B) = ( 273 +10 )^4/ (273 + 20 )^4 uA/uB = $\frac{1}{1}$.15`

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