Two capillary tubes of radii 0.6 cm and 0.3 cm are dipped in the same liquid. The ratio of heights through which the liquid will rise in the tubes is ______.

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Two capillary tubes of radii 0.6 cm and 0.3 cm are dipped in the same liquid. The ratio of heights through which the liquid will rise in the tubes is 1 : 2. Explanation: `h = (2 T)/(r rho g) => h prop 1/r therefore h_1/h_2 = r_2/r_1 therefore h_1/h_2 = 0.$\frac{3}{0}$.6 = 1 : 2`

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